How to graph 3x-y+3=0 and 2x+6y-5=0?

How to graph 3x-y+3=0 and 2x+6y-5=0? Topic: Corresponding angles homework help
June 19, 2019 / By Deven
Question: i have a homework about finding the equation of the bisector of the obtuse angle between this lines 3x-y+3=0 and 2x+6y-5=0 the problem is i dont know how to graph or draw 3x-y+3=0 and 2x+6y-5=0 please help me how to graph or draw it plz explain it briefly
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Best Answers: How to graph 3x-y+3=0 and 2x+6y-5=0?

Candice Candice | 7 days ago
Take Different values of x or y and get corresponding values for y or x, and on 2D graph put these (x,y) points and join them (minimum 2 points for an equation of a line)....... For 3x-y+3=0 : x=1 then y=6, x=2 then y=9 and form a line by joining two points (1,6) and (2,9)..... Same process with second line....
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We found more questions related to the topic: Corresponding angles homework help

Candice Originally Answered: How do you graph y = -2/3x + 1 & 4x+6y+8=0?
First write the statement correctly: y = -2x/3 + 1 This has exactly one possible interpretation. The way you wrote it can be interpreted as y = (-2/3)x or y = -2/(3x) and that can not be allowed. Since the equation is already in slope-intercept form we can avoid the usual table of values. The first point of the graph is given in the equation: (0, 1). That is why we appreciate the slope-intercept form. Mark a point on your graph paper on the y axis at y=1. Now the slope is -2/3. The minus means the line goes down as you move left to right. The 2/3 means you go 3 units to the right and 2 units down. That takes you to (3, -1) so put a mark there. Now get a straightedge and draw a line through those two points and that is your graph. 4x+6y+8=0 The usual approach is to make a table of values, assuming something and calculating a value for the other one, then drawing the graph through those points. But for a straight line it's easier to convert to the slope-intercept form. 4x+6y+8=0 The rule is you can do any valid operation on both sides of an equation and it will still be equal. So subtract 4x, the subtract 8. 6y = -4x - 8 Divide by 6. y = -2x/3 - 4/3 Graph this same as above.

Amaryllis Amaryllis
3x - y + 3 = 0 3x + 3 = y y = 3x + 3 y-intercept is 3, and slope is 3 Mark a point on the y-axis at (0, 3). Then go up 3 and over 1 to the right for the slope of 3 = 3/1. Mark another point there at (1, 6). Draw a line through the two points. 2x + 6y - 5 = 0 6y = -2x + 5 y = (-1/3)x + 5/6 y-intercept is 5/6, and slope is -1/3. Make a point on the y-axis at (0. 5/6), which is just below (0, 1). From that point, go up 5 and over 6 to the right for the slope of 5/6. Make another point there. Draw a line through those points. By the way, the two lines are perpendicular, so the bisector forms a 45° angle.
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Wallis Wallis
put it into y=Mx+b form -6y=9-3x Move 3x over -6y=-3x+9 Divide by -6y to isolate y -6y/-6=-3x/-6+9/-6 y=1/2x-3/2 On grid paper -3/2 or -1.5 is your y intercept. Draw a point. Then draw another point, up 1 (.5) and over 2 (2). Draw line to connect the two points.
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Rudolph Rudolph
Plot two points on the graph which satisfy the first equation(the values of 3x and y should give you the number on the right hand side).Join the two points with a line and extend it. Now plot two points on the graph which satisfy the second equation.Join the two points with a line and extend it. The point where two lines intersect is the solution to those two equations.Hope this helps. CHEERS!!!
👍 28 | 👎 -11

Rudolph Originally Answered: Graph Help?
The left one that goes up and down is always the Y axis. If your graph is over a period of time, then the easiest way is to make the X axis (running from left to right) the date axis and the temperature the Y axis. You can put "0" anywhere you like, and if there are negative numbers you probably want to go from perhaps 110 degrees to -30 degrees. You always go just a bit more than the two extremes. Draw a heavier line where "0" os at so your readers will be able to understand better. If the two variables are altitude and air temp, then I suggest you use air temp on the Y axis and altitude for the X axis, as that will give you nice rising lines left to right as you go higher in elevation. Good luck.

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